1113433134113 has 2 divisors, whose sum is σ = 1113433134114. Its totient is φ = 1113433134112.

The previous prime is 1113433134097. The next prime is 1113433134161. The reversal of 1113433134113 is 3114313343111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1042220475664 + 71212658449 = 1020892^2 + 266857^2 .

It is an emirp because it is prime and its reverse (3114313343111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113433134113 - 2⁴ = 1113433134097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113433131113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556716567056 + 556716567057.

It is an arithmetic number, because the mean of its divisors is an integer number (556716567057).

Almost surely, 2^{1113433134113} is an apocalyptic number.

It is an amenable number.

1113433134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113433134113 is an equidigital number, since it uses as much as digits as its factorization.

1113433134113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 29.

Adding to 1113433134113 its reverse (3114313343111), we get a palindrome (4227746477224).

The spelling of 1113433134113 in words is "one trillion, one hundred thirteen billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred thirteen".