11134333000103 has 4 divisors (see below), whose sum is σ = 11134429291368. Its totient is φ = 11134236708840.

The previous prime is 11134333000081. The next prime is 11134333000117. The reversal of 11134333000103 is 30100033343111.

11134333000103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11134333000103 - 2¹⁶ = 11134332934567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11134833000103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47971976 + ... + 48203517.

It is an arithmetic number, because the mean of its divisors is an integer number (2783607322842).

Almost surely, 2^{11134333000103} is an apocalyptic number.

11134333000103 is a deficient number, since it is larger than the sum of its proper divisors (96291265).

11134333000103 is an equidigital number, since it uses as much as digits as its factorization.

11134333000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96291264.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 11134333000103 its reverse (30100033343111), we get a palindrome (41234366343214).

The spelling of 11134333000103 in words is "eleven trillion, one hundred thirty-four billion, three hundred thirty-three million, one hundred three", and thus it is an aban number.