Base | Representation |
---|---|
bin | 10000001100111110011… |
… | …101010100010101010101 |
3 | 10221102222212002011211201 |
4 | 100030332131110111111 |
5 | 121220313231340032 |
6 | 2211302001432501 |
7 | 143305122156226 |
oct | 20147635242525 |
9 | 3842885064751 |
10 | 1113444402517 |
11 | 39a233379657 |
12 | 15b96233b731 |
13 | 80cc7266c35 |
14 | 3bc68c7524d |
15 | 1de6ae378e7 |
hex | 1033e754555 |
1113444402517 has 2 divisors, whose sum is σ = 1113444402518. Its totient is φ = 1113444402516.
The previous prime is 1113444402493. The next prime is 1113444402599. The reversal of 1113444402517 is 7152044443111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 835266217041 + 278178185476 = 913929^2 + 527426^2 .
It is an emirp because it is prime and its reverse (7152044443111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113444402517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113444403517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556722201258 + 556722201259.
It is an arithmetic number, because the mean of its divisors is an integer number (556722201259).
Almost surely, 21113444402517 is an apocalyptic number.
It is an amenable number.
1113444402517 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113444402517 is an equidigital number, since it uses as much as digits as its factorization.
1113444402517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 53760, while the sum is 37.
Adding to 1113444402517 its reverse (7152044443111), we get a palindrome (8265488845628).
The spelling of 1113444402517 in words is "one trillion, one hundred thirteen billion, four hundred forty-four million, four hundred two thousand, five hundred seventeen".
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