Base | Representation |
---|---|
bin | 10000001100111110011… |
… | …101010100010100111101 |
3 | 10221102222212002011210211 |
4 | 100030332131110110331 |
5 | 121220313231334433 |
6 | 2211302001432421 |
7 | 143305122156163 |
oct | 20147635242475 |
9 | 3842885064724 |
10 | 1113444402493 |
11 | 39a233379635 |
12 | 15b96233b711 |
13 | 80cc7266c17 |
14 | 3bc68c75233 |
15 | 1de6ae378cd |
hex | 1033e75453d |
1113444402493 has 2 divisors, whose sum is σ = 1113444402494. Its totient is φ = 1113444402492.
The previous prime is 1113444402491. The next prime is 1113444402517. The reversal of 1113444402493 is 3942044443111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 696802554009 + 416641848484 = 834747^2 + 645478^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113444402493 - 21 = 1113444402491 is a prime.
Together with 1113444402491, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113444402491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556722201246 + 556722201247.
It is an arithmetic number, because the mean of its divisors is an integer number (556722201247).
Almost surely, 21113444402493 is an apocalyptic number.
It is an amenable number.
1113444402493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113444402493 is an equidigital number, since it uses as much as digits as its factorization.
1113444402493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 40.
The spelling of 1113444402493 in words is "one trillion, one hundred thirteen billion, four hundred forty-four million, four hundred two thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •