Base | Representation |
---|---|
bin | 110011110110101000… |
… | …1101001110101101011 |
3 | 101122102112002122012212 |
4 | 1213231101221311223 |
5 | 3311023340313121 |
6 | 123053352155335 |
7 | 11021323654061 |
oct | 1475521516553 |
9 | 348375078185 |
10 | 111355010411 |
11 | 43253000527 |
12 | 196b8698b4b |
13 | a668155a08 |
14 | 5565144031 |
15 | 2d6b05225b |
hex | 19ed469d6b |
111355010411 has 2 divisors, whose sum is σ = 111355010412. Its totient is φ = 111355010410.
The previous prime is 111355010369. The next prime is 111355010413. The reversal of 111355010411 is 114010553111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111355010411 - 222 = 111350816107 is a prime.
It is a super-3 number, since 3×1113550104113 (a number of 34 digits) contains 333 as substring.
It is a Sophie Germain prime.
Together with 111355010413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111355010413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55677505205 + 55677505206.
It is an arithmetic number, because the mean of its divisors is an integer number (55677505206).
Almost surely, 2111355010411 is an apocalyptic number.
111355010411 is a deficient number, since it is larger than the sum of its proper divisors (1).
111355010411 is an equidigital number, since it uses as much as digits as its factorization.
111355010411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 23.
Adding to 111355010411 its reverse (114010553111), we get a palindrome (225365563522).
The spelling of 111355010411 in words is "one hundred eleven billion, three hundred fifty-five million, ten thousand, four hundred eleven".
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