11140104402333 has 12 divisors (see below), whose sum is σ = 16091969798268. Its totient is φ = 7426409552640.

The previous prime is 11140104402319. The next prime is 11140104402359. The reversal of 11140104402333 is 33320440104111.

11140104402333 is a `hidden beast` number, since 11 + 140 + 104 + 402 + 3 + 3 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 992069784729 + 10148034617604 = 996027^2 + 3185598^2 .

It is not a de Polignac number, because 11140104402333 - 2²⁵ = 11140070847901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11140104402297 and 11140104402306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11140104402233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27010260 + ... + 27419597.

It is an arithmetic number, because the mean of its divisors is an integer number (1340997483189).

Almost surely, 2^{11140104402333} is an apocalyptic number.

It is an amenable number.

11140104402333 is a deficient number, since it is larger than the sum of its proper divisors (4951865395935).

11140104402333 is a wasteful number, since it uses less digits than its factorization.

11140104402333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54452604 (or 54452601 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 11140104402333 its reverse (33320440104111), we get a palindrome (44460544506444).

The spelling of 11140104402333 in words is "eleven trillion, one hundred forty billion, one hundred four million, four hundred two thousand, three hundred thirty-three".