111401140201303 has 2 divisors, whose sum is σ = 111401140201304. Its totient is φ = 111401140201302.

The previous prime is 111401140201259. The next prime is 111401140201313. The reversal of 111401140201303 is 303102041104111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111401140201303 is a prime.

It is a super-2 number, since 2×111401140201303² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111401140201313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55700570100651 + 55700570100652.

It is an arithmetic number, because the mean of its divisors is an integer number (55700570100652).

Almost surely, 2^{111401140201303} is an apocalyptic number.

111401140201303 is a deficient number, since it is larger than the sum of its proper divisors (1).

111401140201303 is an equidigital number, since it uses as much as digits as its factorization.

111401140201303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 111401140201303 its reverse (303102041104111), we get a palindrome (414503181305414).

The spelling of 111401140201303 in words is "one hundred eleven trillion, four hundred one billion, one hundred forty million, two hundred one thousand, three hundred three".