111401213013001 has 2 divisors, whose sum is σ = 111401213013002. Its totient is φ = 111401213013000.

The previous prime is 111401213012993. The next prime is 111401213013007. The reversal of 111401213013001 is 100310312104111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107281534982400 + 4119678030601 = 10357680^2 + 2029699^2 .

It is a cyclic number.

It is not a de Polignac number, because 111401213013001 - 2³ = 111401213012993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111401213013001.

It is not a weakly prime, because it can be changed into another prime (111401213013007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55700606506500 + 55700606506501.

It is an arithmetic number, because the mean of its divisors is an integer number (55700606506501).

Almost surely, 2^{111401213013001} is an apocalyptic number.

It is an amenable number.

111401213013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

111401213013001 is an equidigital number, since it uses as much as digits as its factorization.

111401213013001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 111401213013001 its reverse (100310312104111), we get a palindrome (211711525117112).

The spelling of 111401213013001 in words is "one hundred eleven trillion, four hundred one billion, two hundred thirteen million, thirteen thousand, one".