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1114030113307 is a prime number
BaseRepresentation
bin10000001101100001010…
…111101000001000011011
310221111111200012100222221
4100031201113220020123
5121223013202111212
62211440043324511
7143325463502656
oct20154127501033
93844450170887
101114030113307
1139a503a57861
1215baa6520737
138108b6cb877
143bcc297c89d
151dea2581807
hex103615e821b

1114030113307 has 2 divisors, whose sum is σ = 1114030113308. Its totient is φ = 1114030113306.

The previous prime is 1114030113299. The next prime is 1114030113331. The reversal of 1114030113307 is 7033110304111.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (7033110304111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114030113307 - 23 = 1114030113299 is a prime.

It is not a weakly prime, because it can be changed into another prime (1114030113337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557015056653 + 557015056654.

It is an arithmetic number, because the mean of its divisors is an integer number (557015056654).

Almost surely, 21114030113307 is an apocalyptic number.

1114030113307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114030113307 is an equidigital number, since it uses as much as digits as its factorization.

1114030113307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1114030113307 its reverse (7033110304111), we get a palindrome (8147140417418).

The spelling of 1114030113307 in words is "one trillion, one hundred fourteen billion, thirty million, one hundred thirteen thousand, three hundred seven".