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1114031414014 = 2557015707007
BaseRepresentation
bin10000001101100001011…
…100100101101011111110
310221111111202122110020021
4100031201130211223332
5121223014020222024
62211440131242354
7143325510531061
oct20154134455376
93844452573207
101114031414014
1139a504766022
1215baa6a493ba
138108ba6590c
143bcc2bda8d8
151dea273bde4
hex10361725afe

1114031414014 has 4 divisors (see below), whose sum is σ = 1671047121024. Its totient is φ = 557015707006.

The previous prime is 1114031413987. The next prime is 1114031414017. The reversal of 1114031414014 is 4104141304111.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1114031414014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1114031414017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278507853502 + ... + 278507853505.

It is an arithmetic number, because the mean of its divisors is an integer number (417761780256).

Almost surely, 21114031414014 is an apocalyptic number.

1114031414014 is a deficient number, since it is larger than the sum of its proper divisors (557015707010).

1114031414014 is an equidigital number, since it uses as much as digits as its factorization.

1114031414014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 557015707009.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1114031414014 its reverse (4104141304111), we get a palindrome (5218172718125).

The spelling of 1114031414014 in words is "one trillion, one hundred fourteen billion, thirty-one million, four hundred fourteen thousand, fourteen".

Divisors: 1 2 557015707007 1114031414014