Search a number
-
+
111403270247341 is a prime number
BaseRepresentation
bin11001010101001000011000…
…010110011001001110101101
3112121110001022110002100120211
4121111020120112121032231
5104100212344140403331
61032533542243142421
732315422614023452
oct3125103026311655
9477401273070524
10111403270247341
1132550952860736
12105b2849974a11
134a2138b571117
141d71d389bd829
15cd2cc49e98b1
hex6552185993ad

111403270247341 has 2 divisors, whose sum is σ = 111403270247342. Its totient is φ = 111403270247340.

The previous prime is 111403270247317. The next prime is 111403270247411. The reversal of 111403270247341 is 143742072304111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81180928922116 + 30222341325225 = 9010046^2 + 5497485^2 .

It is a cyclic number.

It is not a de Polignac number, because 111403270247341 - 221 = 111403268150189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111403270247294 and 111403270247303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111403270247641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55701635123670 + 55701635123671.

It is an arithmetic number, because the mean of its divisors is an integer number (55701635123671).

Almost surely, 2111403270247341 is an apocalyptic number.

It is an amenable number.

111403270247341 is a deficient number, since it is larger than the sum of its proper divisors (1).

111403270247341 is an equidigital number, since it uses as much as digits as its factorization.

111403270247341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112896, while the sum is 40.

The spelling of 111403270247341 in words is "one hundred eleven trillion, four hundred three billion, two hundred seventy million, two hundred forty-seven thousand, three hundred forty-one".