11140335133 has 2 divisors, whose sum is σ = 11140335134. Its totient is φ = 11140335132.

The previous prime is 11140335097. The next prime is 11140335149. The reversal of 11140335133 is 33153304111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6190227684 + 4950107449 = 78678^2 + 70357^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11140335133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11140335098 and 11140335107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11140635133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570167566 + 5570167567.

It is an arithmetic number, because the mean of its divisors is an integer number (5570167567).

Almost surely, 2^11140335133 is an apocalyptic number.

It is an amenable number.

11140335133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140335133 is an equidigital number, since it uses as much as digits as its factorization.

11140335133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 11140335133 its reverse (33153304111), we get a palindrome (44293639244).

The spelling of 11140335133 in words is "eleven billion, one hundred forty million, three hundred thirty-five thousand, one hundred thirty-three".