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1114104114343 = 11101282192213
BaseRepresentation
bin10000001101100101110…
…001111010110010100111
310221111200211110000100001
4100031211301322302213
5121223141123124333
62211451245402131
7143330352502303
oct20154561726247
93844624400301
101114104114343
1139a541800940
1215bb07269347
13810a0b3b56c
143bccc722d03
151dea8cecb7d
hex10365c7aca7

1114104114343 has 4 divisors (see below), whose sum is σ = 1215386306568. Its totient is φ = 1012821922120.

The previous prime is 1114104114317. The next prime is 1114104114437. The reversal of 1114104114343 is 3434114014111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1114104114343 - 213 = 1114104106151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1114104114143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50641096096 + ... + 50641096117.

It is an arithmetic number, because the mean of its divisors is an integer number (303846576642).

Almost surely, 21114104114343 is an apocalyptic number.

1114104114343 is a deficient number, since it is larger than the sum of its proper divisors (101282192225).

1114104114343 is a wasteful number, since it uses less digits than its factorization.

1114104114343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101282192224.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 1114104114343 its reverse (3434114014111), we get a palindrome (4548218128454).

The spelling of 1114104114343 in words is "one trillion, one hundred fourteen billion, one hundred four million, one hundred fourteen thousand, three hundred forty-three".

Divisors: 1 11 101282192213 1114104114343