Base | Representation |
---|---|
bin | 10100110000000111… |
… | …10001111100010111 |
3 | 1001202102212121111121 |
4 | 22120003301330113 |
5 | 140304102444143 |
6 | 5041303344411 |
7 | 543041316361 |
oct | 123003617427 |
9 | 31672777447 |
10 | 11141062423 |
11 | 47a7926107 |
12 | 21ab152107 |
13 | 108721743a |
14 | 77990dd31 |
15 | 4531557ed |
hex | 2980f1f17 |
11141062423 has 2 divisors, whose sum is σ = 11141062424. Its totient is φ = 11141062422.
The previous prime is 11141062393. The next prime is 11141062447. The reversal of 11141062423 is 32426014111.
11141062423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11141062423 - 213 = 11141054231 is a prime.
It is a super-3 number, since 3×111410624233 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11141062123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570531211 + 5570531212.
It is an arithmetic number, because the mean of its divisors is an integer number (5570531212).
Almost surely, 211141062423 is an apocalyptic number.
11141062423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141062423 is an equidigital number, since it uses as much as digits as its factorization.
11141062423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 11141062423 its reverse (32426014111), we get a palindrome (43567076534).
The spelling of 11141062423 in words is "eleven billion, one hundred forty-one million, sixty-two thousand, four hundred twenty-three".
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