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1114121340253 is a prime number
BaseRepresentation
bin10000001101100110110…
…011101000010101011101
310221111202000212011211201
4100031212303220111131
5121223210030342003
62211453102515501
7143330652065515
oct20154663502535
93844660764751
101114121340253
1139a5504a6a29
1215bb10b95b91
13810a45900cc
143bcd0b28845
151deaa5a1b1d
hex10366ce855d

1114121340253 has 2 divisors, whose sum is σ = 1114121340254. Its totient is φ = 1114121340252.

The previous prime is 1114121340119. The next prime is 1114121340271. The reversal of 1114121340253 is 3520431214111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 638500079844 + 475621260409 = 799062^2 + 689653^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114121340253 - 217 = 1114121209181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1114121340853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557060670126 + 557060670127.

It is an arithmetic number, because the mean of its divisors is an integer number (557060670127).

Almost surely, 21114121340253 is an apocalyptic number.

It is an amenable number.

1114121340253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114121340253 is an equidigital number, since it uses as much as digits as its factorization.

1114121340253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 1114121340253 its reverse (3520431214111), we get a palindrome (4634552554364).

The spelling of 1114121340253 in words is "one trillion, one hundred fourteen billion, one hundred twenty-one million, three hundred forty thousand, two hundred fifty-three".