Base | Representation |
---|---|
bin | 10000001101100110110… |
… | …011101000010101011101 |
3 | 10221111202000212011211201 |
4 | 100031212303220111131 |
5 | 121223210030342003 |
6 | 2211453102515501 |
7 | 143330652065515 |
oct | 20154663502535 |
9 | 3844660764751 |
10 | 1114121340253 |
11 | 39a5504a6a29 |
12 | 15bb10b95b91 |
13 | 810a45900cc |
14 | 3bcd0b28845 |
15 | 1deaa5a1b1d |
hex | 10366ce855d |
1114121340253 has 2 divisors, whose sum is σ = 1114121340254. Its totient is φ = 1114121340252.
The previous prime is 1114121340119. The next prime is 1114121340271. The reversal of 1114121340253 is 3520431214111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 638500079844 + 475621260409 = 799062^2 + 689653^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114121340253 - 217 = 1114121209181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1114121340853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557060670126 + 557060670127.
It is an arithmetic number, because the mean of its divisors is an integer number (557060670127).
Almost surely, 21114121340253 is an apocalyptic number.
It is an amenable number.
1114121340253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114121340253 is an equidigital number, since it uses as much as digits as its factorization.
1114121340253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 1114121340253 its reverse (3520431214111), we get a palindrome (4634552554364).
The spelling of 1114121340253 in words is "one trillion, one hundred fourteen billion, one hundred twenty-one million, three hundred forty thousand, two hundred fifty-three".
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