1114121340853 has 2 divisors, whose sum is σ = 1114121340854. Its totient is φ = 1114121340852.

The previous prime is 1114121340817. The next prime is 1114121340887. The reversal of 1114121340853 is 3580431214111.

It is an a-pointer prime, because the next prime (1114121340887) can be obtained adding 1114121340853 to its sum of digits (34).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 751130755684 + 362990585169 = 866678^2 + 602487^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114121340853 - 2¹³ = 1114121332661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1114121340253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557060670426 + 557060670427.

It is an arithmetic number, because the mean of its divisors is an integer number (557060670427).

Almost surely, 2^{1114121340853} is an apocalyptic number.

It is an amenable number.

1114121340853 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114121340853 is an equidigital number, since it uses as much as digits as its factorization.

1114121340853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 34.

Adding to 1114121340853 its reverse (3580431214111), we get a palindrome (4694552554964).

The spelling of 1114121340853 in words is "one trillion, one hundred fourteen billion, one hundred twenty-one million, three hundred forty thousand, eight hundred fifty-three".