11141313040132 has 12 divisors (see below), whose sum is σ = 21269779440336. Its totient is φ = 5064233200040.

The previous prime is 11141313040127. The next prime is 11141313040139. The reversal of 11141313040132 is 23104031314111.

It is a junction number, because it is equal to n+sod(n) for n = 11141313040097 and 11141313040106.

It is not an unprimeable number, because it can be changed into a prime (11141313040139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126605829958 + ... + 126605830045.

It is an arithmetic number, because the mean of its divisors is an integer number (1772481620028).

Almost surely, 2^{11141313040132} is an apocalyptic number.

It is an amenable number.

11141313040132 is a deficient number, since it is larger than the sum of its proper divisors (10128466400204).

11141313040132 is a wasteful number, since it uses less digits than its factorization.

11141313040132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 253211660018 (or 253211660016 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 11141313040132 its reverse (23104031314111), we get a palindrome (34245344354243).

The spelling of 11141313040132 in words is "eleven trillion, one hundred forty-one billion, three hundred thirteen million, forty thousand, one hundred thirty-two".