111432202152137 has 8 divisors (see below), whose sum is σ = 113570076791880. Its totient is φ = 109295637892480.

The previous prime is 111432202152127. The next prime is 111432202152179. The reversal of 111432202152137 is 731251202234111.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 34109092409401 + 77323109742736 = 5840299^2 + 8793356^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111432202152137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111432202152097 and 111432202152106.

It is not an unprimeable number, because it can be changed into a prime (111432202152127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 327423314 + ... + 327763467.

It is an arithmetic number, because the mean of its divisors is an integer number (14196259598985).

Almost surely, 2^{111432202152137} is an apocalyptic number.

It is an amenable number.

111432202152137 is a deficient number, since it is larger than the sum of its proper divisors (2137874639743).

111432202152137 is an equidigital number, since it uses as much as digits as its factorization.

111432202152137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655190043.

The product of its (nonzero) digits is 20160, while the sum is 35.

Adding to 111432202152137 its reverse (731251202234111), we get a palindrome (842683404386248).

The spelling of 111432202152137 in words is "one hundred eleven trillion, four hundred thirty-two billion, two hundred two million, one hundred fifty-two thousand, one hundred thirty-seven".