Base | Representation |
---|---|
bin | 1010001000101000001100… |
… | …1001010100101110010101 |
3 | 1110110021220220100202211101 |
4 | 2202022003021110232111 |
5 | 2430033032412102201 |
6 | 35411103205310101 |
7 | 2230036326200215 |
oct | 242120311245625 |
9 | 43407826322741 |
10 | 11143345425301 |
11 | 3606958a93651 |
12 | 12bb7a3a05331 |
13 | 62aa7511143b |
14 | 2a74ab206245 |
15 | 144ce5e52d01 |
hex | a2283254b95 |
11143345425301 has 8 divisors (see below), whose sum is σ = 11151528574464. Its totient is φ = 11135165233920.
The previous prime is 11143345425229. The next prime is 11143345425337. The reversal of 11143345425301 is 10352454334111.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11143345425301 - 213 = 11143345417109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11143345425361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6826636 + ... + 8299978.
It is an arithmetic number, because the mean of its divisors is an integer number (1393941071808).
Almost surely, 211143345425301 is an apocalyptic number.
It is an amenable number.
11143345425301 is a deficient number, since it is larger than the sum of its proper divisors (8183149163).
11143345425301 is a wasteful number, since it uses less digits than its factorization.
11143345425301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1478891.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 11143345425301 its reverse (10352454334111), we get a palindrome (21495799759412).
The spelling of 11143345425301 in words is "eleven trillion, one hundred forty-three billion, three hundred forty-five million, four hundred twenty-five thousand, three hundred one".
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