Base | Representation |
---|---|
bin | 100001001101100… |
… | …1011010000000111 |
3 | 2212122222102011101 |
4 | 1002123023100013 |
5 | 4240242421411 |
6 | 302325520531 |
7 | 36421262401 |
oct | 10233132007 |
9 | 2778872141 |
10 | 1114420231 |
11 | 522074461 |
12 | 271273147 |
13 | 149b5c472 |
14 | a8013b71 |
15 | 67c838c1 |
hex | 426cb407 |
1114420231 has 4 divisors (see below), whose sum is σ = 1114546464. Its totient is φ = 1114294000.
The previous prime is 1114420213. The next prime is 1114420247. The reversal of 1114420231 is 1320244111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1320244111 = 29 ⋅45525659.
It is a cyclic number.
It is not a de Polignac number, because 1114420231 - 25 = 1114420199 is a prime.
It is a super-2 number, since 2×11144202312 = 2483864902524186722, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1114420199 and 1114420208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1114420031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48790 + ... + 67891.
It is an arithmetic number, because the mean of its divisors is an integer number (278636616).
Almost surely, 21114420231 is an apocalyptic number.
1114420231 is a deficient number, since it is larger than the sum of its proper divisors (126233).
1114420231 is an equidigital number, since it uses as much as digits as its factorization.
1114420231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126232.
The product of its (nonzero) digits is 192, while the sum is 19.
The square root of 1114420231 is about 33382.9332294213. The cubic root of 1114420231 is about 1036.7713700739.
Adding to 1114420231 its reverse (1320244111), we get a palindrome (2434664342).
It can be divided in two parts, 11144 and 20231, that added together give a triangular number (31375 = T250).
The spelling of 1114420231 in words is "one billion, one hundred fourteen million, four hundred twenty thousand, two hundred thirty-one".
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