Base | Representation |
---|---|
bin | 11001010101110110110011… |
… | …000110100110000000010111 |
3 | 112121121210221221122210121202 |
4 | 121111312303012212000113 |
5 | 104102021432432322403 |
6 | 1033012504044103115 |
7 | 32322135665164451 |
oct | 3125666306460027 |
9 | 477553857583552 |
10 | 111453111214103 |
11 | 3256aaa978175a |
12 | 10600439534a9b |
13 | 4a25ca239b429 |
14 | 1d745061532d1 |
15 | cd4240428688 |
hex | 655db31a6017 |
111453111214103 has 2 divisors, whose sum is σ = 111453111214104. Its totient is φ = 111453111214102.
The previous prime is 111453111214087. The next prime is 111453111214127. The reversal of 111453111214103 is 301412111354111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111453111214103 - 24 = 111453111214087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111453111214183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55726555607051 + 55726555607052.
It is an arithmetic number, because the mean of its divisors is an integer number (55726555607052).
Almost surely, 2111453111214103 is an apocalyptic number.
111453111214103 is a deficient number, since it is larger than the sum of its proper divisors (1).
111453111214103 is an equidigital number, since it uses as much as digits as its factorization.
111453111214103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 29.
Adding to 111453111214103 its reverse (301412111354111), we get a palindrome (412865222568214).
The spelling of 111453111214103 in words is "one hundred eleven trillion, four hundred fifty-three billion, one hundred eleven million, two hundred fourteen thousand, one hundred three".
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