Base | Representation |
---|---|
bin | 1010001000111010011001… |
… | …1010100110110100000111 |
3 | 1110110202112110112212120011 |
4 | 2202032212122212310013 |
5 | 2430123034411010303 |
6 | 35413232132251051 |
7 | 2230301404361161 |
oct | 242164632466407 |
9 | 43422473485504 |
10 | 11148232125703 |
11 | 3608a36445a22 |
12 | 1300728470a87 |
13 | 62b373650b3a |
14 | 2a7812213931 |
15 | 144ecee7916d |
hex | a23a66a6d07 |
11148232125703 has 2 divisors, whose sum is σ = 11148232125704. Its totient is φ = 11148232125702.
The previous prime is 11148232125643. The next prime is 11148232125727. The reversal of 11148232125703 is 30752123284111.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (30752123284111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11148232125703 - 213 = 11148232117511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11148232120703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5574116062851 + 5574116062852.
It is an arithmetic number, because the mean of its divisors is an integer number (5574116062852).
Almost surely, 211148232125703 is an apocalyptic number.
11148232125703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11148232125703 is an equidigital number, since it uses as much as digits as its factorization.
11148232125703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 40.
The spelling of 11148232125703 in words is "eleven trillion, one hundred forty-eight billion, two hundred thirty-two million, one hundred twenty-five thousand, seven hundred three".
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