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11148513301 is a prime number
BaseRepresentation
bin10100110001000000…
…01101000000010101
31001202221220011012001
422120200031000111
5140313004411201
65042131155301
7543161541142
oct123040150025
931687804161
1011148513301
114801055062
1221b1745b31
131088925943
1477a8cd3c9
15453b28301
hex29880d015

11148513301 has 2 divisors, whose sum is σ = 11148513302. Its totient is φ = 11148513300.

The previous prime is 11148513269. The next prime is 11148513347. The reversal of 11148513301 is 10331584111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11108949201 + 39564100 = 105399^2 + 6290^2 .

It is a cyclic number.

It is not a de Polignac number, because 11148513301 - 25 = 11148513269 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11148513301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11148513361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5574256650 + 5574256651.

It is an arithmetic number, because the mean of its divisors is an integer number (5574256651).

Almost surely, 211148513301 is an apocalyptic number.

It is an amenable number.

11148513301 is a deficient number, since it is larger than the sum of its proper divisors (1).

11148513301 is an equidigital number, since it uses as much as digits as its factorization.

11148513301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 28.

The spelling of 11148513301 in words is "eleven billion, one hundred forty-eight million, five hundred thirteen thousand, three hundred one".