Base | Representation |
---|---|
bin | 110011111010110010… |
… | …0111011001011101101 |
3 | 101122210020011021001201 |
4 | 1213311210323023231 |
5 | 3311320013424132 |
6 | 123115245205501 |
7 | 11024634512446 |
oct | 1476544731355 |
9 | 348706137051 |
10 | 111494279917 |
11 | 43314683799 |
12 | 19737260891 |
13 | a68ac686c7 |
14 | 55798382cd |
15 | 2d783b22e7 |
hex | 19f593b2ed |
111494279917 has 2 divisors, whose sum is σ = 111494279918. Its totient is φ = 111494279916.
The previous prime is 111494279899. The next prime is 111494279989. The reversal of 111494279917 is 719972494111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109250741961 + 2243537956 = 330531^2 + 47366^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111494279917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111494279317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55747139958 + 55747139959.
It is an arithmetic number, because the mean of its divisors is an integer number (55747139959).
Almost surely, 2111494279917 is an apocalyptic number.
It is an amenable number.
111494279917 is a deficient number, since it is larger than the sum of its proper divisors (1).
111494279917 is an equidigital number, since it uses as much as digits as its factorization.
111494279917 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1143072, while the sum is 55.
The spelling of 111494279917 in words is "one hundred eleven billion, four hundred ninety-four million, two hundred seventy-nine thousand, nine hundred seventeen".
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