1115054234141 has 2 divisors, whose sum is σ = 1115054234142. Its totient is φ = 1115054234140.

The previous prime is 1115054234117. The next prime is 1115054234143. The reversal of 1115054234141 is 1414324505111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1081955709241 + 33098524900 = 1040171^2 + 181930^2 .

It is a cyclic number.

It is not a de Polignac number, because 1115054234141 - 2³⁴ = 1097874364957 is a prime.

Together with 1115054234143, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1115054234098 and 1115054234107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1115054234143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557527117070 + 557527117071.

It is an arithmetic number, because the mean of its divisors is an integer number (557527117071).

Almost surely, 2^{1115054234141} is an apocalyptic number.

It is an amenable number.

1115054234141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1115054234141 is an equidigital number, since it uses as much as digits as its factorization.

1115054234141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 32.

Adding to 1115054234141 its reverse (1414324505111), we get a palindrome (2529378739252).

The spelling of 1115054234141 in words is "one trillion, one hundred fifteen billion, fifty-four million, two hundred thirty-four thousand, one hundred forty-one".