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1115054433413 is a prime number
BaseRepresentation
bin10000001110011110011…
…011000110010010000101
310221121011001122020000122
4100032132123012102011
5121232112413332123
62212125434151325
7143363042204654
oct20163633062205
93847131566018
101115054433413
1139a98a1816a8
12160131582545
13811c29a263b
143bd7ca1b19b
151e012468bc8
hex1039e6c6485

1115054433413 has 2 divisors, whose sum is σ = 1115054433414. Its totient is φ = 1115054433412.

The previous prime is 1115054433407. The next prime is 1115054433421. The reversal of 1115054433413 is 3143344505111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 734437002049 + 380617431364 = 856993^2 + 616942^2 .

It is an emirp because it is prime and its reverse (3143344505111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1115054433413 - 218 = 1115054171269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1115054433013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557527216706 + 557527216707.

It is an arithmetic number, because the mean of its divisors is an integer number (557527216707).

Almost surely, 21115054433413 is an apocalyptic number.

It is an amenable number.

1115054433413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1115054433413 is an equidigital number, since it uses as much as digits as its factorization.

1115054433413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 1115054433413 its reverse (3143344505111), we get a palindrome (4258398938524).

The spelling of 1115054433413 in words is "one trillion, one hundred fifteen billion, fifty-four million, four hundred thirty-three thousand, four hundred thirteen".