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11151000053 is a prime number
BaseRepresentation
bin10100110001010011…
…01100000111110101
31001210010120111100222
422120221230013311
5140314124000203
65042300344125
7543221636144
oct123051540765
931703514328
1011151000053
1148024a3426
1221b2545045
1310892b67ab
1477ad7975b
15453e6a038
hex298a6c1f5

11151000053 has 2 divisors, whose sum is σ = 11151000054. Its totient is φ = 11151000052.

The previous prime is 11151000013. The next prime is 11151000061. The reversal of 11151000053 is 35000015111.

11151000053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9215616004 + 1935384049 = 95998^2 + 43993^2 .

It is a cyclic number.

It is not a de Polignac number, because 11151000053 - 216 = 11150934517 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11150999995 and 11151000040.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11151000013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5575500026 + 5575500027.

It is an arithmetic number, because the mean of its divisors is an integer number (5575500027).

Almost surely, 211151000053 is an apocalyptic number.

It is an amenable number.

11151000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11151000053 is an equidigital number, since it uses as much as digits as its factorization.

11151000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75, while the sum is 17.

Adding to 11151000053 its reverse (35000015111), we get a palindrome (46151015164).

The spelling of 11151000053 in words is "eleven billion, one hundred fifty-one million, fifty-three", and thus it is an aban number.