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11153140252413 = 39673844584713
BaseRepresentation
bin1010001001001100101011…
…1101100111111011111101
31110111020012112001112122220
42202103022331213323331
52430213112401034123
635415403142355553
72230534132641405
oct242231275477375
943436175045586
1011153140252413
113610024a02195
12130167812bbb9
1362b976452c23
142a7b59ddb805
151451bacd3ce3
hexa24caf67efd

11153140252413 has 8 divisors (see below), whose sum is σ = 14886232012608. Its totient is φ = 7427737663584.

The previous prime is 11153140252411. The next prime is 11153140252447. The reversal of 11153140252413 is 31425204135111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11153140252413 - 21 = 11153140252411 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11153140252411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1922289456 + ... + 1922295257.

It is an arithmetic number, because the mean of its divisors is an integer number (1860779001576).

Almost surely, 211153140252413 is an apocalyptic number.

It is an amenable number.

11153140252413 is a deficient number, since it is larger than the sum of its proper divisors (3733091760195).

11153140252413 is an equidigital number, since it uses as much as digits as its factorization.

11153140252413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3844585683.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 11153140252413 its reverse (31425204135111), we get a palindrome (42578344387524).

The spelling of 11153140252413 in words is "eleven trillion, one hundred fifty-three billion, one hundred forty million, two hundred fifty-two thousand, four hundred thirteen".

Divisors: 1 3 967 2901 3844584713 11533754139 3717713417471 11153140252413