Base | Representation |
---|---|
bin | 10100110001101100… |
… | …10101010100100101 |
3 | 1001210100210212222111 |
4 | 22120312111110211 |
5 | 140321001031113 |
6 | 5042455401021 |
7 | 543262052305 |
oct | 123066252445 |
9 | 31710725874 |
10 | 11154314533 |
11 | 480435766a |
12 | 21b3683171 |
13 | 1089ba731b |
14 | 77b59d605 |
15 | 4543c213d |
hex | 298d95525 |
11154314533 has 4 divisors (see below), whose sum is σ = 11810450700. Its totient is φ = 10498178368.
The previous prime is 11154314503. The next prime is 11154314539. The reversal of 11154314533 is 33541345111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5319951844 + 5834362689 = 72938^2 + 76383^2 .
It is not a de Polignac number, because 11154314533 - 221 = 11152217381 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11154314495 and 11154314504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11154314539) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328068058 + ... + 328068091.
It is an arithmetic number, because the mean of its divisors is an integer number (2952612675).
Almost surely, 211154314533 is an apocalyptic number.
It is an amenable number.
11154314533 is a deficient number, since it is larger than the sum of its proper divisors (656136167).
11154314533 is an equidigital number, since it uses as much as digits as its factorization.
11154314533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 656136166.
The product of its digits is 10800, while the sum is 31.
Adding to 11154314533 its reverse (33541345111), we get a palindrome (44695659644).
The spelling of 11154314533 in words is "eleven billion, one hundred fifty-four million, three hundred fourteen thousand, five hundred thirty-three".
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