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11155242824837 is a prime number
BaseRepresentation
bin1010001001010100100001…
…0010010011010010000101
31110111102122001102021210122
42202111020102103102011
52430231414130343322
635420351532031325
72230640213341226
oct242251022232205
943442561367718
1011155242824837
113610a03837a51
121301b64302545
1362bc1cc31917
142a7cb935724d
151452906a8442
hexa2548493485

11155242824837 has 2 divisors, whose sum is σ = 11155242824838. Its totient is φ = 11155242824836.

The previous prime is 11155242824821. The next prime is 11155242824839. The reversal of 11155242824837 is 73842824255111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10272082690081 + 883160134756 = 3205009^2 + 939766^2 .

It is a cyclic number.

It is not a de Polignac number, because 11155242824837 - 24 = 11155242824821 is a prime.

Together with 11155242824839, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11155242824839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577621412418 + 5577621412419.

It is an arithmetic number, because the mean of its divisors is an integer number (5577621412419).

Almost surely, 211155242824837 is an apocalyptic number.

It is an amenable number.

11155242824837 is a deficient number, since it is larger than the sum of its proper divisors (1).

11155242824837 is an equidigital number, since it uses as much as digits as its factorization.

11155242824837 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4300800, while the sum is 53.

The spelling of 11155242824837 in words is "eleven trillion, one hundred fifty-five billion, two hundred forty-two million, eight hundred twenty-four thousand, eight hundred thirty-seven".