11155430413133 has 8 divisors (see below), whose sum is σ = 11486724007416. Its totient is φ = 10826956339200.

The previous prime is 11155430413117. The next prime is 11155430413147. The reversal of 11155430413133 is 33131403455111.

It can be written as a sum of positive squares in 4 ways, for example, as 244181257609 + 10911249155524 = 494147^2 + 3303218^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11155430413133 - 2⁴ = 11155430413117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11155430413093 and 11155430413102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11155430413033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 704872058 + ... + 704887883.

It is an arithmetic number, because the mean of its divisors is an integer number (1435840500927).

Almost surely, 2^{11155430413133} is an apocalyptic number.

It is an amenable number.

11155430413133 is a deficient number, since it is larger than the sum of its proper divisors (331293594283).

11155430413133 is a wasteful number, since it uses less digits than its factorization.

11155430413133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1409760175.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 11155430413133 its reverse (33131403455111), we get a palindrome (44286833868244).

The spelling of 11155430413133 in words is "eleven trillion, one hundred fifty-five billion, four hundred thirty million, four hundred thirteen thousand, one hundred thirty-three".