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11155501655071 is a prime number
BaseRepresentation
bin1010001001010101011110…
…1101101010010000011111
31110111110022002110020010121
42202111113231222100133
52430232431410430241
635420433335415411
72230646505351304
oct242252755522037
943443262406117
1011155501655071
113611026951a34
121302016b24567
1362bc617465c7
142a7d018910ab
151452a8283ad1
hexa2557b6a41f

11155501655071 has 2 divisors, whose sum is σ = 11155501655072. Its totient is φ = 11155501655070.

The previous prime is 11155501655041. The next prime is 11155501655099. The reversal of 11155501655071 is 17055610555111.

It is a strong prime.

It is an emirp because it is prime and its reverse (17055610555111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11155501655071 - 225 = 11155468100639 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11155501655041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577750827535 + 5577750827536.

It is an arithmetic number, because the mean of its divisors is an integer number (5577750827536).

Almost surely, 211155501655071 is an apocalyptic number.

11155501655071 is a deficient number, since it is larger than the sum of its proper divisors (1).

11155501655071 is an equidigital number, since it uses as much as digits as its factorization.

11155501655071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 131250, while the sum is 43.

The spelling of 11155501655071 in words is "eleven trillion, one hundred fifty-five billion, five hundred one million, six hundred fifty-five thousand, seventy-one".