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1117048845733 is a prime number
BaseRepresentation
bin10000010000010101010…
…011001011010110100101
310221210022001110212101121
4100100111103023112211
5121300204001030413
62213055401253541
7143463340345102
oct20202523132645
93853261425347
101117048845733
113a0812a52147
121605a94942b1
138144cc41582
143c0cb85daa9
151e0cc5c5b8d
hex104154cb5a5

1117048845733 has 2 divisors, whose sum is σ = 1117048845734. Its totient is φ = 1117048845732.

The previous prime is 1117048845631. The next prime is 1117048845751. The reversal of 1117048845733 is 3375488407111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1116526128964 + 522716769 = 1056658^2 + 22863^2 .

It is a cyclic number.

It is not a de Polignac number, because 1117048845733 - 221 = 1117046748581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1117048845763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 558524422866 + 558524422867.

It is an arithmetic number, because the mean of its divisors is an integer number (558524422867).

Almost surely, 21117048845733 is an apocalyptic number.

It is an amenable number.

1117048845733 is a deficient number, since it is larger than the sum of its proper divisors (1).

1117048845733 is an equidigital number, since it uses as much as digits as its factorization.

1117048845733 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2257920, while the sum is 52.

The spelling of 1117048845733 in words is "one trillion, one hundred seventeen billion, forty-eight million, eight hundred forty-five thousand, seven hundred thirty-three".