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111838288040161 is a prime number
BaseRepresentation
bin11001011011011101100001…
…011011100101000011100001
3112122222122011120210220200021
4121123131201123211003201
5104124324303214241121
61033505444504153441
732362023015165064
oct3133354133450341
9478878146726607
10111838288040161
11326a9395a87081
1210663014468881
134a533c79c2a17
141d890057a08db
15cde2857da641
hex65b7616e50e1

111838288040161 has 2 divisors, whose sum is σ = 111838288040162. Its totient is φ = 111838288040160.

The previous prime is 111838288040159. The next prime is 111838288040173. The reversal of 111838288040161 is 161040882838111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89056138545936 + 22782149494225 = 9436956^2 + 4773065^2 .

It is a cyclic number.

It is not a de Polignac number, because 111838288040161 - 21 = 111838288040159 is a prime.

Together with 111838288040159, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 111838288040099 and 111838288040108.

It is not a weakly prime, because it can be changed into another prime (111838288020161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55919144020080 + 55919144020081.

It is an arithmetic number, because the mean of its divisors is an integer number (55919144020081).

Almost surely, 2111838288040161 is an apocalyptic number.

It is an amenable number.

111838288040161 is a deficient number, since it is larger than the sum of its proper divisors (1).

111838288040161 is an equidigital number, since it uses as much as digits as its factorization.

111838288040161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 589824, while the sum is 52.

The spelling of 111838288040161 in words is "one hundred eleven trillion, eight hundred thirty-eight billion, two hundred eighty-eight million, forty thousand, one hundred sixty-one".