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112000110113 is a prime number
BaseRepresentation
bin110100001001110111…
…0100000111000100001
3101201002110222002122102
41220103232200320201
53313334012010423
6123241355020145
711043316141163
oct1502356407041
9351073862572
10112000110113
1143554162481
121985873a655
13a73b9b2408
1455c6aaa933
152da79ccc28
hex1a13ba0e21

112000110113 has 2 divisors, whose sum is σ = 112000110114. Its totient is φ = 112000110112.

The previous prime is 112000110097. The next prime is 112000110133. The reversal of 112000110113 is 311011000211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78931778704 + 33068331409 = 280948^2 + 181847^2 .

It is a cyclic number.

It is not a de Polignac number, because 112000110113 - 24 = 112000110097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112000110094 and 112000110103.

It is not a weakly prime, because it can be changed into another prime (112000110133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000055056 + 56000055057.

It is an arithmetic number, because the mean of its divisors is an integer number (56000055057).

Almost surely, 2112000110113 is an apocalyptic number.

It is an amenable number.

112000110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112000110113 is an equidigital number, since it uses as much as digits as its factorization.

112000110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 112000110113 its reverse (311011000211), we get a palindrome (423011110324).

The spelling of 112000110113 in words is "one hundred twelve billion, one hundred ten thousand, one hundred thirteen".