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11200051127 is a prime number
BaseRepresentation
bin10100110111001001…
…10011011110110111
31001220112212112210102
422123210303132313
5140414203114002
65051211544315
7544355602166
oct123344633667
931815775712
1011200051127
114828156201
122206a5b09b
1310964cbcb5
147836a73dd
15458408a02
hex29b9337b7

11200051127 has 2 divisors, whose sum is σ = 11200051128. Its totient is φ = 11200051126.

The previous prime is 11200051123. The next prime is 11200051141. The reversal of 11200051127 is 72115000211.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (72115000211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11200051127 - 22 = 11200051123 is a prime.

It is a super-2 number, since 2×112000511272 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11200051099 and 11200051108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11200051123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600025563 + 5600025564.

It is an arithmetic number, because the mean of its divisors is an integer number (5600025564).

Almost surely, 211200051127 is an apocalyptic number.

11200051127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200051127 is an equidigital number, since it uses as much as digits as its factorization.

11200051127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 140, while the sum is 20.

Adding to 11200051127 its reverse (72115000211), we get a palindrome (83315051338).

The spelling of 11200051127 in words is "eleven billion, two hundred million, fifty-one thousand, one hundred twenty-seven".