Base | Representation |
---|---|
bin | 110100001001111000… |
… | …0100101110000011011 |
3 | 101201002111222202012211 |
4 | 1220103300211300123 |
5 | 3313334131414423 |
6 | 123241414415551 |
7 | 11043323566003 |
oct | 1502360456033 |
9 | 351074882184 |
10 | 112000654363 |
11 | 435544a4374 |
12 | 198589615b7 |
13 | a73bb43060 |
14 | 55c6bad003 |
15 | 2da7a8910d |
hex | 1a13c25c1b |
112000654363 has 4 divisors (see below), whose sum is σ = 120616089328. Its totient is φ = 103385219400.
The previous prime is 112000654333. The next prime is 112000654373. The reversal of 112000654363 is 363456000211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112000654363 - 229 = 111463783451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112000654333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4307717463 + ... + 4307717488.
It is an arithmetic number, because the mean of its divisors is an integer number (30154022332).
Almost surely, 2112000654363 is an apocalyptic number.
112000654363 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
112000654363 is a deficient number, since it is larger than the sum of its proper divisors (8615434965).
112000654363 is an equidigital number, since it uses as much as digits as its factorization.
112000654363 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8615434964.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 112000654363 its reverse (363456000211), we get a palindrome (475456654574).
The spelling of 112000654363 in words is "one hundred twelve billion, six hundred fifty-four thousand, three hundred sixty-three".
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