Base | Representation |
---|---|
bin | 110100001001111000… |
… | …1110101001000001111 |
3 | 101201002112121021011212 |
4 | 1220103301311020033 |
5 | 3313334222320341 |
6 | 123241425405035 |
7 | 11043326421563 |
oct | 1502361651017 |
9 | 351075537155 |
10 | 112000979471 |
11 | 435546a6657 |
12 | 19858a9977b |
13 | a73bc28024 |
14 | 55c6c556a3 |
15 | 2da7b005eb |
hex | 1a13c7520f |
112000979471 has 2 divisors, whose sum is σ = 112000979472. Its totient is φ = 112000979470.
The previous prime is 112000979411. The next prime is 112000979473. The reversal of 112000979471 is 174979000211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112000979471 - 26 = 112000979407 is a prime.
It is a super-3 number, since 3×1120009794713 (a number of 34 digits) contains 333 as substring.
Together with 112000979473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112000979473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000489735 + 56000489736.
It is an arithmetic number, because the mean of its divisors is an integer number (56000489736).
Almost surely, 2112000979471 is an apocalyptic number.
112000979471 is a deficient number, since it is larger than the sum of its proper divisors (1).
112000979471 is an equidigital number, since it uses as much as digits as its factorization.
112000979471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31752, while the sum is 41.
Adding to 112000979471 its reverse (174979000211), we get a palindrome (286979979682).
The spelling of 112000979471 in words is "one hundred twelve billion, nine hundred seventy-nine thousand, four hundred seventy-one".
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