Base | Representation |
---|---|
bin | 110100001001111001… |
… | …0010100101111011001 |
3 | 101201002112211211210111 |
4 | 1220103302110233121 |
5 | 3313334240441303 |
6 | 123241432244321 |
7 | 11043330501226 |
oct | 1502362245731 |
9 | 351075754714 |
10 | 112001108953 |
11 | 43554784968 |
12 | 19858b406a1 |
13 | a73bc71c46 |
14 | 55c6c8a94d |
15 | 2da7b28b6d |
hex | 1a13c94bd9 |
112001108953 has 2 divisors, whose sum is σ = 112001108954. Its totient is φ = 112001108952.
The previous prime is 112001108951. The next prime is 112001108977. The reversal of 112001108953 is 359801100211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99535833049 + 12465275904 = 315493^2 + 111648^2 .
It is a cyclic number.
It is not a de Polignac number, because 112001108953 - 21 = 112001108951 is a prime.
Together with 112001108951, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (112001108951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000554476 + 56000554477.
It is an arithmetic number, because the mean of its divisors is an integer number (56000554477).
Almost surely, 2112001108953 is an apocalyptic number.
It is an amenable number.
112001108953 is a deficient number, since it is larger than the sum of its proper divisors (1).
112001108953 is an equidigital number, since it uses as much as digits as its factorization.
112001108953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 31.
The spelling of 112001108953 in words is "one hundred twelve billion, one million, one hundred eight thousand, nine hundred fifty-three".
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