112003311013001 has 4 divisors (see below), whose sum is σ = 112006155869904. Its totient is φ = 112000466156100.

The previous prime is 112003311012977. The next prime is 112003311013003. The reversal of 112003311013001 is 100310113300211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112003311013001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (112003311013003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1422369395 + ... + 1422448136.

It is an arithmetic number, because the mean of its divisors is an integer number (28001538967476).

Almost surely, 2^{112003311013001} is an apocalyptic number.

It is an amenable number.

112003311013001 is a deficient number, since it is larger than the sum of its proper divisors (2844856903).

112003311013001 is an equidigital number, since it uses as much as digits as its factorization.

112003311013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2844856902.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 112003311013001 its reverse (100310113300211), we get a palindrome (212313424313212).

The spelling of 112003311013001 in words is "one hundred twelve trillion, three billion, three hundred eleven million, thirteen thousand, one".