11201002013 has 2 divisors, whose sum is σ = 11201002014. Its totient is φ = 11201002012.

The previous prime is 11201002003. The next prime is 11201002039. The reversal of 11201002013 is 31020010211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10878907204 + 322094809 = 104302^2 + 17947^2 .

It is a cyclic number.

It is not a de Polignac number, because 11201002013 - 2⁶ = 11201001949 is a prime.

It is a super-3 number, since 3×11201002013³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11201001985 and 11201002003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11201002003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600501006 + 5600501007.

It is an arithmetic number, because the mean of its divisors is an integer number (5600501007).

Almost surely, 2^11201002013 is an apocalyptic number.

It is an amenable number.

11201002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11201002013 is an equidigital number, since it uses as much as digits as its factorization.

11201002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11201002013 its reverse (31020010211), we get a palindrome (42221012224).

The spelling of 11201002013 in words is "eleven billion, two hundred one million, two thousand, thirteen".