Base | Representation |
---|---|
bin | 1010001011111111011001… |
… | …0000010001010101001110 |
3 | 1110122211000200212020011012 |
4 | 2202333312100101111032 |
5 | 2432004333431413402 |
6 | 35453415222325222 |
7 | 2234152656164564 |
oct | 242776620212516 |
9 | 43584020766135 |
10 | 11201111201102 |
11 | 3629401295a29 |
12 | 130aa25589812 |
13 | 63334ca16374 |
14 | 2aa1cb06da34 |
15 | 146577478452 |
hex | a2ff641154e |
11201111201102 has 4 divisors (see below), whose sum is σ = 16801666801656. Its totient is φ = 5600555600550.
The previous prime is 11201111201089. The next prime is 11201111201131. The reversal of 11201111201102 is 20110211110211.
11201111201102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×112011112011023 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2800277800274 + ... + 2800277800277.
It is an arithmetic number, because the mean of its divisors is an integer number (4200416700414).
Almost surely, 211201111201102 is an apocalyptic number.
11201111201102 is a deficient number, since it is larger than the sum of its proper divisors (5600555600554).
11201111201102 is an equidigital number, since it uses as much as digits as its factorization.
11201111201102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5600555600553.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 11201111201102 its reverse (20110211110211), we get a palindrome (31311322311313).
The spelling of 11201111201102 in words is "eleven trillion, two hundred one billion, one hundred eleven million, two hundred one thousand, one hundred two".
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