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112012002312149 is a prime number
BaseRepresentation
bin11001011101111111010011…
…100110111011111111010101
3112200121020120000212021002202
4121131333103212323333111
5104140201040042442044
61034121334204014245
732410412560141412
oct3135772346737725
9480536500767082
10112012002312149
1132766029181815
1210690814b31385
134a668c02c9884
141d935a4851109
15ce3a5126ac4e
hex65dfd39bbfd5

112012002312149 has 2 divisors, whose sum is σ = 112012002312150. Its totient is φ = 112012002312148.

The previous prime is 112012002312101. The next prime is 112012002312151. The reversal of 112012002312149 is 941213200210211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87840944522500 + 24171057789649 = 9372350^2 + 4916407^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112012002312149 is a prime.

Together with 112012002312151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112012002315149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006001156074 + 56006001156075.

It is an arithmetic number, because the mean of its divisors is an integer number (56006001156075).

Almost surely, 2112012002312149 is an apocalyptic number.

It is an amenable number.

112012002312149 is a deficient number, since it is larger than the sum of its proper divisors (1).

112012002312149 is an equidigital number, since it uses as much as digits as its factorization.

112012002312149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 29.

The spelling of 112012002312149 in words is "one hundred twelve trillion, twelve billion, two million, three hundred twelve thousand, one hundred forty-nine".