Base | Representation |
---|---|
bin | 11001011101111111011001… |
… | …011011101101101100110101 |
3 | 112200121020210211202000100212 |
4 | 121131333121123231230311 |
5 | 104140201240102031313 |
6 | 1034121352014315205 |
7 | 32410415154563003 |
oct | 3135773133555465 |
9 | 480536724660325 |
10 | 112012100033333 |
11 | 32766079357125 |
12 | 106908417b8b05 |
13 | 4a66907623066 |
14 | 1d935b380ba73 |
15 | ce3a59b203a8 |
hex | 65dfd96edb35 |
112012100033333 has 2 divisors, whose sum is σ = 112012100033334. Its totient is φ = 112012100033332.
The previous prime is 112012100033329. The next prime is 112012100033359. The reversal of 112012100033333 is 333330001210211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 93220898079409 + 18791201953924 = 9655097^2 + 4334882^2 .
It is a cyclic number.
It is not a de Polignac number, because 112012100033333 - 22 = 112012100033329 is a prime.
It is a super-2 number, since 2×1120121000333332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112012100033299 and 112012100033308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112012100033303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006050016666 + 56006050016667.
It is an arithmetic number, because the mean of its divisors is an integer number (56006050016667).
Almost surely, 2112012100033333 is an apocalyptic number.
It is an amenable number.
112012100033333 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012100033333 is an equidigital number, since it uses as much as digits as its factorization.
112012100033333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 112012100033333 its reverse (333330001210211), we get a palindrome (445342101243544).
The spelling of 112012100033333 in words is "one hundred twelve trillion, twelve billion, one hundred million, thirty-three thousand, three hundred thirty-three".
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