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112012202220120 = 233253730672741873
BaseRepresentation
bin11001011101111111011111…
…100001100001101001011000
3112200121021001222000122021200
4121131333133201201221120
5104140201442232020440
61034121410104434200
732410420535263446
oct3135773741415130
9480537058018250
10112012202220120
1132766121001614
121069086ba78960
134a66922851007
141d935c320bb96
15ce3a63aa7c30
hex65dfdf861a58

112012202220120 has 192 divisors, whose sum is σ = 374000606946720. Its totient is φ = 29053138931712.

The previous prime is 112012202220119. The next prime is 112012202220221. The reversal of 112012202220120 is 21022202210211.

It is a happy number.

112012202220120 is a `hidden beast` number, since 1 + 1 + 201 + 220 + 2 + 220 + 1 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 112012202220093 and 112012202220102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 39481504 + ... + 42223376.

Almost surely, 2112012202220120 is an apocalyptic number.

112012202220120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112012202220120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (187000303473360).

112012202220120 is an abundant number, since it is smaller than the sum of its proper divisors (261988404726600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112012202220120 is a wasteful number, since it uses less digits than its factorization.

112012202220120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2744994 (or 2744987 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 18.

Adding to 112012202220120 its reverse (21022202210211), we get a palindrome (133034404430331).

Subtracting from 112012202220120 its reverse (21022202210211), we obtain a palindrome (90990000009909).

The spelling of 112012202220120 in words is "one hundred twelve trillion, twelve billion, two hundred two million, two hundred twenty thousand, one hundred twenty".