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112013011030212 = 2233171911035730841
BaseRepresentation
bin11001011110000000001111…
…101110111001000011000100
3112200121100011022221110011000
4121132000033232321003010
5104140210121310431322
61034122022240213300
732410446556122405
oct3136001756710304
9480540138843130
10112013011030212
11327664a660a606
1210690a5690a230
134a66a21299c76
141d9365c7cb9ac
15ce3aaeac03ac
hex65e00fbb90c4

112013011030212 has 192 divisors, whose sum is σ = 309136442388480. Its totient is φ = 34952842137600.

The previous prime is 112013011030201. The next prime is 112013011030231. The reversal of 112013011030212 is 212030110310211.

112013011030212 is a `hidden beast` number, since 1 + 120 + 1 + 301 + 1 + 0 + 30 + 212 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3631935912 + ... + 3631966752.

It is an arithmetic number, because the mean of its divisors is an integer number (1610085637440).

Almost surely, 2112013011030212 is an apocalyptic number.

112013011030212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112013011030212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154568221194240).

112013011030212 is an abundant number, since it is smaller than the sum of its proper divisors (197123431358268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112013011030212 is a wasteful number, since it uses less digits than its factorization.

112013011030212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41419 (or 41411 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 112013011030212 its reverse (212030110310211), we get a palindrome (324043121340423).

The spelling of 112013011030212 in words is "one hundred twelve trillion, thirteen billion, eleven million, thirty thousand, two hundred twelve".