1120130114143 has 2 divisors, whose sum is σ = 1120130114144. Its totient is φ = 1120130114142.

The previous prime is 1120130114113. The next prime is 1120130114209. The reversal of 1120130114143 is 3414110310211.

It is a weak prime.

It is an emirp because it is prime and its reverse (3414110310211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1120130114143 - 2¹³ = 1120130105951 is a prime.

It is a super-2 number, since 2×1120130114143² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1120130114113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560065057071 + 560065057072.

It is an arithmetic number, because the mean of its divisors is an integer number (560065057072).

Almost surely, 2^{1120130114143} is an apocalyptic number.

1120130114143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120130114143 is an equidigital number, since it uses as much as digits as its factorization.

1120130114143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1120130114143 its reverse (3414110310211), we get a palindrome (4534240424354).

The spelling of 1120130114143 in words is "one trillion, one hundred twenty billion, one hundred thirty million, one hundred fourteen thousand, one hundred forty-three".