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1120134432353 is a prime number
BaseRepresentation
bin10000010011001101001…
…101110000011001100001
310222002021002112220111112
4100103031031300121201
5121323013403313403
62214325504153105
7143632655402336
oct20231515603141
93862232486445
101120134432353
113a205675a032
1216110a908795
1381822290c81
143c30158498d
151e20d4239d8
hex104cd370661

1120134432353 has 2 divisors, whose sum is σ = 1120134432354. Its totient is φ = 1120134432352.

The previous prime is 1120134432247. The next prime is 1120134432401. The reversal of 1120134432353 is 3532344310211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 999376097344 + 120758335009 = 999688^2 + 347503^2 .

It is a cyclic number.

It is not a de Polignac number, because 1120134432353 - 216 = 1120134366817 is a prime.

It is a super-2 number, since 2×11201344323532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1120131432353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560067216176 + 560067216177.

It is an arithmetic number, because the mean of its divisors is an integer number (560067216177).

Almost surely, 21120134432353 is an apocalyptic number.

It is an amenable number.

1120134432353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120134432353 is an equidigital number, since it uses as much as digits as its factorization.

1120134432353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 1120134432353 its reverse (3532344310211), we get a palindrome (4652478742564).

The spelling of 1120134432353 in words is "one trillion, one hundred twenty billion, one hundred thirty-four million, four hundred thirty-two thousand, three hundred fifty-three".