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11201383 is a prime number
BaseRepresentation
bin101010101110…
…101101100111
3210002002102001
4222232231213
510331421013
61040030131
7164132044
oct52565547
923062361
1011201383
116360846
123902347
13242264b
1416b81cb
15eb3ddd
hexaaeb67

11201383 has 2 divisors, whose sum is σ = 11201384. Its totient is φ = 11201382.

The previous prime is 11201381. The next prime is 11201387. The reversal of 11201383 is 38310211.

It is a weak prime.

It is an emirp because it is prime and its reverse (38310211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11201383 - 21 = 11201381 is a prime.

It is a super-2 number, since 2×112013832 = 250941962225378, which contains 22 as substring.

Together with 11201381, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11201383.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11201381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600691 + 5600692.

It is an arithmetic number, because the mean of its divisors is an integer number (5600692).

Almost surely, 211201383 is an apocalyptic number.

11201383 is a deficient number, since it is larger than the sum of its proper divisors (1).

11201383 is an equidigital number, since it uses as much as digits as its factorization.

11201383 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 11201383 is about 3346.8467249039. The cubic root of 11201383 is about 223.7469972444.

Adding to 11201383 its reverse (38310211), we get a palindrome (49511594).

The spelling of 11201383 in words is "eleven million, two hundred one thousand, three hundred eighty-three".