112014013 has 2 divisors, whose sum is σ = 112014014. Its totient is φ = 112014012.

The previous prime is 112013999. The next prime is 112014043. The reversal of 112014013 is 310410211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90973444 + 21040569 = 9538^2 + 4587^2 .

It is a cyclic number.

It is not a de Polignac number, because 112014013 - 2⁵ = 112013981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112013984 and 112014002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112014043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56007006 + 56007007.

It is an arithmetic number, because the mean of its divisors is an integer number (56007007).

Almost surely, 2^112014013 is an apocalyptic number.

It is an amenable number.

112014013 is a deficient number, since it is larger than the sum of its proper divisors (1).

112014013 is an equidigital number, since it uses as much as digits as its factorization.

112014013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 112014013 is about 10583.6672755714. The cubic root of 112014013 is about 482.0485551655.

Adding to 112014013 its reverse (310410211), we get a palindrome (422424224).

The spelling of 112014013 in words is "one hundred twelve million, fourteen thousand, thirteen".